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3sum problem (finding triplets) in better than o (n^2) asked 13 years, 5 months ago modified 2 years, 8 months ago viewed 6k times Leaving the question of is o (1) faster than o (log n), exampling it with my code. I'm studying the 3 sum to implement it on my own, and came across the following implementation with the rules
Given an array s of n integers, are there elements a, b, c in s such that a + b + c =. Asked3 years, 4 months ago modified 2 years, 8 months ago viewed 627 times 2 in the scenario i present to you, my solution is supposed to represent o (n^2 * log n), and the pointers solution, which i assume is the fastest way to resolve the 3sum problem, represents o (n^2 * 1) This looks like the standard approach to solving 3sum in quadratic time
However, i disagree with the other answers concerning space complexity and believe it is quadratic as there can be quadratically many distinct triples summing to 0.
Solving the leetcode 3sum problem in python asked 7 years, 1 month ago modified 7 years, 1 month ago viewed 2k times I am working on the 3sum problem (taken from leetcode), which takes a list as input and finds all unique triplets in the lists such that a+b+c=0 A problem called 3sum smaller on leetcode asks Given an array of n integers nums and a target, find the number of index triplets i, j, k with 0 <= i < j < k < n that satisfy the condi.
Given an array a of integers, find any 3 of them that sum to any given t I saw this on some online post, which claims it has a o(nlogn) solution For 2 numbers, i know hashtable could help for o. I tried an alternative approach to the 3sum problem
Given an array find all triplets that sum up to a given number
Basically the approach is this Once a pair of elements (say a[. How can i make use of binary search for improving my algorithms time complexity I'm reviewing time complexity for some interviews &
I'm having trouble making my algorithm more time efficient.
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