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I've read about the difference between double precision and single precision How can i make cout print a double using full precision? However, in most cases, float and double seem to be interchangeable, i.e

Using one or the other does not seem to affec. In my earlier question i was printing a double using cout that got rounded when i wasn't expecting it The 53 bits of double s give about 16 digits of precision

The 24 bits of float s give about 7 digits of precision.

From what i have read, a value of data type double has an approximate precision of 15 decimal places However, when i use a number whose decimal representation repeats, such as 1.0/7.0, i find tha. 494 a double is not an integer, so the cast won't work Note the difference between the double class and the double primitive

Also note that a double is a number, so it has the method intvalue, which you can use to get the value as a primitive int. Using long double i get 18/19 = 0.947368421052631578., and 947368421052631578 is the repeating decimal Using double i get 0.947368421052631526.however, the former is correct Double d = ((double) num) / denom

But is there another way to get the correct double result

I don't like casting primitives, who knows what may happen. Long double vs double i am unable to understand the difference between between long double and double in c and c++

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